IP地址處理模塊IPy之多網絡計算

判斷IP地址和網段是否包含于另一個網段中

>>> IP('10.10.10.0/24')<IP('10.10.11.0/24')

True

>>> '10.10.12.11' in IP('10.10.11.0/24')   

False

>>> '10.10.11.11' in IP('10.10.11.0/24') 

True

網段兩個網段是否有重疊

>>> IP('192.168.0.0/23').overlaps('192.168.1.0/24')    #1表示有重疊

1

>>> IP('192.168.2.0/23').overlaps('192.168.1.0/24')    #0表示沒重疊

示例

根據輸入的IP或子網返回網絡、掩碼、廣播、反向解析、子網數、IP類型

[root@localhost python2.6]# cat netsimple1.py 

#!/usr/bin/env python

#by lineqi

#create time 2015-09-04

from IPy import IP

ip_s = raw_input('please input an IP or net-range:')

ips = IP(ip_s)

if len(ips) >1:

        print('net :%s ' % ips.net())

        print('netmask :%s ' % ips.netmask())

        print('broadcast :%s ' % ips.broadcast())

        print('revese address :%s ' % ips.reverseNames()[0])    #輸出第1個子網地址反向解析

        print('subnet :%s ' % len(ips))                         #輸出網絡子網數

else:

        print('reverse address :%s' % ips.reverseNames())

print('iptype :%s' % ips.iptype())

[root@localhost python2.6]# python netsimple1.py 

please input an IP or net-range:192.168.1.0/28

net :192.168.1.0 

netmask :255.255.255.240 

broadcast :192.168.1.15 

revese address :0.1.168.192.in-addr.arpa. 

subnet :16 

iptype :PRIVATE

[root@localhost python2.6]# python netsimple1.py     

please input an IP or net-range:192.168.1.23

reverse address :['23.1.168.192.in-addr.arpa.']

iptype :PRIVATE