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Java中怎么封裝一個樹形結構,針對這個問題,這篇文章詳細介紹了相對應的分析和解答,希望可以幫助更多想解決這個問題的小伙伴找到更簡單易行的方法。
1、實體類
@data public class PublishServiceType implements Comparable<PublishServiceType>{ /** * */ private static final long serialVersionUID = -3572108154932898825L; /* * @see [code] * @comment 類型標識 */ private String code; /* * @see {createtime} * @comment 創建時間 */ private java.util.Date createtime; /* * @see {defaultmanual} * @comment 服務類型默認使用手冊 */ private String defaultmanual; /* * @see {description} * @comment 服務類型描述 */ private String description; /* * @see {id} * @comment 主鍵 */ private String id; /* * @see {isdelete} * @comment 是否可以刪除 */ private Integer isdelete; /* * @see {lastmodifytime} * @comment 最近修改時間 */ private java.util.Date lastmodifytime; /* * @see {name} * @comment 服務類型名稱 */ private String name; /* * @see {parentid} * @comment 服務類型父節點 */ private String parentid; /** * 排序 */ private Integer sort; private List<PublishServiceType>children; }
2、數據封裝
@Override public List<PublishServiceType> findList(String name) { List<PublishServiceType>list = publishServiceTypeMapper.findByName(name); if (JudgeUtil.isEmpty(list)){ return null; } //父子級組裝 return parentAndChildren(list); } private List<PublishServiceType>parentAndChildren(List<PublishServiceType> list){ //最頂層根節點 List<PublishServiceType>rootList = new ArrayList<>(); //非最頂層根節點 List<PublishServiceType>bodyList = new ArrayList<>(); for (PublishServiceType publishServiceType : list) { if (StringUtils.isBlank(publishServiceType.getParentid())){ rootList.add(publishServiceType); }else{ bodyList.add(publishServiceType); } } return getTree(rootList,bodyList); } public List<PublishServiceType> getTree(List<PublishServiceType>rootList, List<PublishServiceType>bodyList){ if (!JudgeUtil.isEmpty(bodyList)){ //聲明一個map,用來過濾已操作過的數據 Map<String,String> map = new HashMap<>(bodyList.size()); rootList.forEach(parent->getChild(parent,bodyList,map)); return rootList; }else{ return rootList; } } private void getChild(PublishServiceType parent,List<PublishServiceType>bodyList, Map<String,String> map){ List<PublishServiceType>childList = new ArrayList<>(); bodyList.stream().filter(c->!map.containsKey(c.getId())) .filter(c->c.getParentid().equals(parent.getId())) .forEach(c->{ map.put(c.getId(),c.getParentid()); getChild(c,bodyList,map); childList.add(c); }); parent.setChildren(childList); }
3、結果
{ "code": 20000, "message": "成功", "data": [ { "code": null, "createtime": null, "defaultmanual": null, "description": null, "id": "dc1d70b9eb7b4df3bbe8dcc6a93cbd57", "isdelete": -1, "lastmodifytime": null, "name": "基礎服務", "parentid": "", "sort": 1, "children": [ { "code": null, "createtime": null, "defaultmanual": null, "description": null, "id": "b1779671ef1b45e0a9a8a1edbff03f1e", "isdelete": -1, "lastmodifytime": null, "name": "數據源服務", "parentid": "dc1d70b9eb7b4df3bbe8dcc6a93cbd57", "sort": 2, "children": [ { "code": null, "createtime": null, "defaultmanual": null, "description": null, "id": "2a38a8254ec348e9b54c9bf4622f23db", "isdelete": 1, "lastmodifytime": null, "name": "測試添加數據庫服務2", "parentid": "b1779671ef1b45e0a9a8a1edbff03f1e", "sort": null, "children": [] } ] }, { "code": null, "createtime": null, "defaultmanual": null, "description": null, "id": "d4f3b047dc2d467a9b404ded8acf4673", "isdelete": 1, "lastmodifytime": null, "name": "text_lsa", "parentid": "dc1d70b9eb7b4df3bbe8dcc6a93cbd57", "sort": null, "children": [] } ] }, { "code": null, "createtime": null, "defaultmanual": null, "description": null, "id": "af1b4a4d2f074fa19e1dae0a5540a5bf", "isdelete": 1, "lastmodifytime": null, "name": "測試添加1", "parentid": "", "sort": null, "children": [] }, { "code": null, "createtime": null, "defaultmanual": null, "description": null, "id": "62e15d859a224126884888a55df355a7", "isdelete": 1, "lastmodifytime": null, "name": "測試添加2", "parentid": "", "sort": null, "children": [] } ] }
關于Java中怎么封裝一個樹形結構問題的解答就分享到這里了,希望以上內容可以對大家有一定的幫助,如果你還有很多疑惑沒有解開,可以關注億速云行業資訊頻道了解更多相關知識。
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