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今天就跟大家聊聊有關如何用SQL進行集合運算 ,可能很多人都不太了解,為了讓大家更加了解,小編給大家總結了以下內容,希望大家根據這篇文章可以有所收獲。
drop table if exists tbl_a;create table tbl_a( key1 varchar(10), col_1 int4, col_2 int4, col_3 int4 );insert into tbl_a values('A', 2, 3, 4); insert into tbl_a values('B', 0, 7, 9); insert into tbl_a values('c', 5, 1, 6); drop table if exists tbl_b;create table tbl_b( key1 varchar(10), col_1 int4, col_2 int4, col_3 int4 ); insert into tbl_b values('A', 2, 3, 4); insert into tbl_b values('B', 0, 7, 9); insert into tbl_b values('c', 5, 1, 6);-- ## 如果union a b 行數一致則兩張表相等 select count(1) row_cnt from ( select * from tbl_A union select * from tbl_b ) tmp ;
直接求兩表的不同之處
(select * from tbl_a except select * from tbl_b) union all (select * from tbl_b except select * from tbl_a);
建表
drop table if exists skills;create table skills( skill varchar(10) );insert into skills values('oracle'); insert into skills values('unix');insert into skills values('java');drop table if exists empskills;create table empskills( emp varchar(10), skill varchar(10) );insert into empskills values('相田','oracle'); insert into empskills values('相田','unix'); insert into empskills values('相田','java'); insert into empskills values('相田','c#'); insert into empskills values('神奇','oracle'); insert into empskills values('神奇','unix'); insert into empskills values('神奇','java'); insert into empskills values('平井','oracle'); insert into empskills values('平井','unix'); insert into empskills values('平井','PHP'); insert into empskills values('平井','Perl'); insert into empskills values('平井','C++'); insert into empskills values('若田部','Perl'); insert into empskills values('度來','oracle');
--把除法變成減法select distinct emp from empskills es1 where not exists (select skill from skills expect select skill from empskills es2 where es1.emp = es2.emp);
drop table if exists supparts;create table supparts( sup varchar(10), part varchar(10) );insert into supparts values('A', '螺絲'); insert into supparts values('A', '螺母'); insert into supparts values('A', '管子'); insert into supparts values('B', '螺絲'); insert into supparts values('B', '管子'); insert into supparts values('C', '螺絲'); insert into supparts values('C', '螺母'); insert into supparts values('C', '管子'); insert into supparts values('D', '螺絲'); insert into supparts values('D', '管子'); insert into supparts values('E','保險絲'); insert into supparts values('E', '螺母'); insert into supparts values('E', '管子'); insert into supparts values('F','保險絲');
思路: 兩個供應商都經營同種類型的零件 (簡單的按照零件列進行連接) 兩個供應商的零件類型數相同(即存在一一映射)(count限定)
select a.sup s1, b.sup s2 from supparts a, supparts b where a.sup < b.sup -- 生成供應商的全部組合 and a.part = b.part -- 條件1:經營同種類型的零件 group by a.sup, b.suphaving count(*) = (select count(1) -- 條件2:經營的零件的數量種類相同 a = 中間數 from supparts c where c.sup = a.sup) and count(*) = (select count(1) -- 條件2:經營的零件的數量種類相同 b = 中間數 from supparts d where d.sup = b.sup) ;
drop table if exists products;create table products( rowid int4, name1 varchar(10), price int4 );insert into products values(1,'蘋果',50);insert into products values(2,'橘子',100); insert into products values(3,'橘子',100);insert into products values(4,'橘子',100); insert into products values(5,'香蕉',80);-- 刪除重行高效SQL語句(1):通過EXCEPT求補集delete from productswhere rowid in (select rowid -- 全部rowid from products except -- 減去 select max(rowid) -- 要留下的rowid from products group by name1, price );-- 刪除重行高效SQL語句(2):通過not indelete from products where rowid not in (select max(rowid) from products group by name1, price );
-- 改進中用union的比較select case when count(1) = (select count(1) from tbl_A) and count(1) = (select count(1)+1 from tbl_b) then count(1) else '不相等' end row_cnt from ( select * from tbl_A union select * from tbl_b ) tmp ;
看完上述內容,你們對如何用SQL進行集合運算 有進一步的了解嗎?如果還想了解更多知識或者相關內容,請關注億速云行業資訊頻道,感謝大家的支持。
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