iOS UIView中hitTest:withEvent方法觸摸的位置設置

#pragma?mark?在UIView視圖結構中查找點擊view的觸摸事件
-?(UIView?*)hitTest:(CGPoint)point?withEvent:(UIEvent?*)event{
????
????//?如果不可以交互?|?隱藏?|?透明度太小?3者任意一個都忽略不能點擊
????if(!self.userInteractionEnabled?||?self.hidden?||?self.alpha<=0.01){
????????return?nil;
????}
????if([self?pointInside:point?withEvent:event]){
????????
???????__block?UIView?*hit?=??nil;
????????
????????//NSEnumerationReverse?倒序
????????[self.subviews?enumerateObjectsWithOptions:(NSEnumerationReverse)?usingBlock:^(__kindof?UIView?*?_Nonnull?obj,?NSUInteger?idx,?BOOL?*?_Nonnull?stop)?{
????????????
????????????///進行坐標轉化
????????????CGPoint?vonverPoint?=?[self?convertPoint:point?toView:obj];
????????????hit?=?[obj?hitTest:vonverPoint?withEvent:event];
????????????if(hit){
????????????????*stop?=?YES;
????????????}
????????}];
????????if(hit){
????????????return?hit;
????????}else{
????????????return?self;
????????}
????}else{
????????return?nil;
????}
}

#pragma?mark?觸摸的位置是否在當前view視圖中合適的點擊位置
-?(BOOL)pointInside:(CGPoint)point?withEvent:(UIEvent?*)event{
????
????CGFloat?x1?=?point.x;?//?觸摸的x
????CGFloat?y1?=?point.y;?//?觸摸的y
????
????CGFloat?x2?=?self.frame.size.width/2;?//view的?x
????CGFloat?y2?=?self.frame.size.height/2;?//view的?y
????
????
????double?dis?=?sqrt((x1-x2?)*(x1-x2)?+?(y1-y2?)*(y1-y2));?//這里設置自己的判斷，button的大小?或者按鈕中心的一點?或者buton里放置的最大圓等
????if(dis<=self.frame.size.width/2){?//判斷當前觸摸的點是不是自己要點擊的區域
????????return?YES;
????}else{
????????return?NO;
????}
}

在UIView中做的轉盤游戲，我們需要判斷點擊的位置，然后做對應的點擊事件處理，我們就可以用上面的辦法，或者tabBar凸出的部分等都會用到，首先就要了解hitTest是什么，然后他的調用順序才能合理的應用，來極大的縮短時間。